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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Correct Answers Indicted
CHEM 120 Week 8 Final Exam Correct Answers Indicted

CHEM 120 Week 8 Final Exam Correct Answers Indicted 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): 2. (TCO 1)...

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 Chemistry > EXAM REVIEW > CHEM 120 Week 8 Final Exam Review (Fall Session)
CHEM 120 Week 8 Final Exam Review (Fall Session)

Question: Know what is the atomic number, atomic mass, protons, neutrons and electrons Question:Describe the shapes of molecules H2S, CBr4, and PCl3 Question:Calculating types of bonding (ionic, c...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam + Review+ Study Guide
CHEM 120 Week 8 Final Exam + Review+ Study Guide

Page 1 (TCO 12) Transcription is the process by which DNA passes information to (TCO 12) The portion of an enzyme where the substrate “fits ” during the reaction is called the (TCO 12) Which of the...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Jan 2021 (100% CORRECT SOLUTIONS) | Already GRADED A.
CHEM 120 Week 8 Final Exam Jan 2021 (100% CORRECT SOLUTIONS) | Already GRADED A.

6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam (Solved Q & A) | Highly Rated Paper | Already Graded A+
CHEM 120 Week 8 Final Exam (Solved Q & A) | Highly Rated Paper | Already Graded A+

6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Review (Fall Session): Spring 2021
CHEM 120 Week 8 Final Exam Review (Fall Session): Spring 2021

Question: Know what is the atomic number, atomic mass, protons, neutrons and electrons Question:Describe the shapes of molecules H2S, CBr4, and PCl3 Question:Calculating types of bonding (ionic, cov...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Study Guide CERTIFIED WITH ANSWERS
CHEM 120 Week 8 Final Exam Study Guide CERTIFIED WITH ANSWERS

CHEM 120 Week 8 Final Exam Study Guide CERTIFIED WITH ANSWERS Chem20 Final-Exam Study-Guide Terms: A) Metabolism: Chemical reactions that keep cells alive. Divided into 2 classes: Anabolism:...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam
CHEM 120 Week 8 Final Exam

1. Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): 2. Question: (TCO 1) How many mL are in 3.5 pints? Show...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Questions-Answers
CHEM 120 Week 8 Final Exam Questions-Answers

CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points :...

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 Chemistry > EXAM > CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3. (TCO 3) What is the name of the following compound: Zn3P2? (Points : 5) 4. (TCO 3) What is the name of the following compound: AgNO3? (Points : 5) 5. (TCO 6) Calculate the pressure, in atmospheres, of 2.78 mol CO(g) in a 4.25 L tank at 51 degrees C. (Points : 5) 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 273) Thus, T1 = 95 273 = 368. We have V1 (165 mL) & T2 = (25 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Points : 5) 1021mL * 719 mm/745 mmHg = 985.36mL =985mL Using Boyle’s law, P1V1 = P2V2. We have V1 (1021 mL), P1 (719 mmHg) and P2 (745 mmHg). 8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G A C G C, what is the sequence of the other DNA strand? (Points : 10) A A T C G C T G C G
CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3. (TCO 3) What is the name of the following compound: Zn3P2? (Points : 5) 4. (TCO 3) What is the name of the following compound: AgNO3? (Points : 5) 5. (TCO 6) Calculate the pressure, in atmospheres, of 2.78 mol CO(g) in a 4.25 L tank at 51 degrees C. (Points : 5) 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 273) Thus, T1 = 95 273 = 368. We have V1 (165 mL) & T2 = (25 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Points : 5) 1021mL * 719 mm/745 mmHg = 985.36mL =985mL Using Boyle’s law, P1V1 = P2V2. We have V1 (1021 mL), P1 (719 mmHg) and P2 (745 mmHg). 8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G A C G C, what is the sequence of the other DNA strand? (Points : 10) A A T C G C T G C G

CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points :...

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