Pearson Edexcel Level 3 GCE Mathematics Advanced Subsidiary PAPER 1: Pure Mathematics question booklet and mark scheme results November 2021

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pearson-edexcel-gce-question-booklet-mark-scheme-results-november-2021-further-mathematics-advanced-subsidiary-level-in-mathematics-paper-8ma0-01 In this question you should show all stages of your w... orking. Solutions relying on calculator technology are not acceptable. Using algebra, solve the inequality x 2 – x > 20 writing your answer in set notation. (3) _____________________________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ ___________________________________________ In this question you should show all stages of your working. Solutions relying on calculator technology are not acceptable. Given 9 3 81 1 2 x y − + = express y in terms of x, writing your answer in simplest form. (3) _____________________________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ ______________________________________________ Question Scheme Marks AOs 1 Finds critical values x x x x x 2 2 −   − −   = − 20 20 0 5, 4 ( ) M1 1.1b Chooses outside region for their values Eg. x x   − 5, 4 M1 1.1b Presents solution in set notation x x x x : 4 : 5  −      oe A1 2.5 (3) (3 marks) Notes M1: Attempts to find the critical values using an algebraic method. Condone slips but an allowable method should be used and two critical values should be found M1: Chooses the outside region for their critical values. This may appear in incorrect inequalities such as 5 4   − x A1: Presents in set notation as requiredx x x x : 4 : 5  −      Accept x x  −   4 5. Do not accept x x  −  4, 5 Note: If there is a contradiction of their solution on different lines of working do not penalise intermediate working and mark what appears to be their final answer. [Show More]

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