University of California, Los Angeles STATS 10 Introduction to Statistical Reasoning Homework #5

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University of California, Los Angeles STATS 10 Introduction to Statistical Reasoning Homework #5 5.7: Criminal Court Judges a. There are a total of 9 judges listed. The possible outcome would be ... n = 9 (if you would to consider all the possible outcomes to have an equal chance). Possible outcomes would be: James C. Beasley, Carolyn W. Blackett, Lee V. Coffee, John T. Fowlkes, W. Otis Higgs, James M. Lammey, Paula L. Skahan, and W. Mark Ward. b. The outcomes that would make up event A would be n(small a) = 2. The outcomes would be Paula L. Skahan or Carolyn W. Blackett. c. The probability that a case will be assigned to a female judge is 0.222 P(A) = 2/9 = 0.222 d. Outcomes that are in the complement of event A The number of outcomes favorable would be 7 The outcomes would be the male judges. 5.8: Random Assignment of Professors a. List the equally likely outcomes that could occur for assignment of one student to a professor. The possible outcomes would be Peters, Parker, Diaz, Nguyen, and Black. N = 5 b. Suppose the event of interest, event A, is that a teacher is experienced. List the outcomes that make up event A. The possible outcomes would be Peter, Parker, and Nguyen. n(little A) = 3 c. What is the probability that one student will be assigned to an inexperienced teacher? The number of favorable outcomes is 3 The possibility that an experienced teacher would be assigned is ⅗ = 0.6. d. List the outcomes in the complement of event A. Describe this complement in words. A = 2 There are two inexperienced teachers (Black and Diaz). e. What is the probability that one student will be assigned to an inexperienced teacher? ⅖ = 0.4 5.9: Which of the following numbers could ​not ​be probabilities, and why? 1.3- it is more than 1 (the value of a probability can not be more than 1) 150%- it is more than one (when changed to a decimal it would be 1.50) -0.5- it is a negative 5.10- Which of the following numbers could ​not ​be probabilities, and why? The fraction 7/4- when changed into a decimal it would have a value of 1.75 (greater than 1) -10%- this is a negative percent 5.11: Playing Cards (Example 1) a. A heart? There are four different suits, so divide 52 by 4 52/4 = 13 13 of the cards are hearts, so divide that by 52 13/52 = .25 The probability would be 1/4 b. A red card? There are two different colors in a deck, so divide 52 by 2 52/2 = 26 26 of the cards are red, so divide by 52 26/52 = ½ The probability would be ½ c. An ace? There are four cards in the deck that are ace, so divide 4 by 52 4/52 = 1/13 The probability would be 1/13 d. A face card (jack, queen, or king) There are 12 face cards in total, so divide 12 by 52 12/52 = 4.333 The probability would be 3/13 e. A three? There are 4 cards with the number three on them, so divide 4 by 52. 4/52 = 0.76 The probability would be 1/13 5.12: Playing Cards a. A black card? There are two different colors in a deck, so divide 52 by 2 52/2 = 26 26 of the cards are black, so divide by 52 26/52 = ½ The probability would be ½ b. A diamond? 52/4 = 13 13 of the cards are hearts, so divide that by 52 13/52 = .25 The probability would be 1/4 c. A face card (jack, queen, or king)? There are 12 face cards in total, so divide 12 by 52 12/52 = 4.333 The probability would be 3/13 d. A nine? There are 4 cards with the number three on them, so divide 4 by 52. 4/52 = 0.76 The probability would be 1/13 [Show More]

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