Sophia Introduction to Statistics Unit 5 Milestone 5.

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Mike tabulated the following values for heights in inches of seven of his friends: 65, 71, 74, 61, 66, 70, and 72. The sample standard deviation is 4.577. Select the 95% confidence interval for Mike... 's set of data. 59.95 to 76.91 59.95 to 72.67 64.19 to 76.91 64.19 to 72.67 RATIONALE In order to get the 95% CI , we first need to find the critical t-score. Using a t-table, we need to find (n-1) degrees of freedom, or (7-1) = 6 df and the corresponding CI. Using the 95% CI in the bottom row and 6 df on the far left column, we get a t-critical score of 2.447. We also need to calculate the mean: 8/1/2020 Sophia :: Welcome https://capella.sophia.org/spcc/introduction-to-statistics-2/milestone_take_feedbacks/5465629 2/21 So we use the formula to find the confidence interval: The lower bound is: 68.43 - 4.23 = 64.20 The upper bound is: 68.43 +4.23 = 72.66 *note that when rounding you can get values that might be slightly different but the values should be very close to what is calculated here. CONCEPT Confidence Intervals Using the T-Distribution 2 A table represents the number of students who passed or failed an aptitude test at two different campuses. East Campus West Campus Passed 39 45 Failed 61 55 In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association and independence should be performed. What is the expected frequency of East Campus and passed? 39 students 42 students 48.3 students 50.5 students [Show More]

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