GEOMETRY Calc_7.5_Quiz_FINAL Fundamental Theorem of Calculus, Part 2 Quiz

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Calculus Fundamental Theorem of Calculus, Part 2 Quiz MC = 2 points Total = 20 points Answer each of the following problems. Objective 1: Write and use integral functions. Display 3 1) The grap... h shown below is f(x) = 2x – 1. What is the integral that defines the area under this line between x = 1 and x = 5? X Y -4 -2 2 4 -2 8 6 4 2 0 Created with a trial version of Advanced Grapher - http://www.alentum.com/agrapher/ <alt tag = a graph of a straight line of slope 2 and a y-intercept of negative 1> @ The integral function is g(x) = 152t  1 <alt tag = the integral from 1 to 5 of the quantity 2t minus 1>dt. *a. g(x) = 152t  1 <alt tag = the integral from 1 to 5 of the quantity 2t minus 1>dt b. g(x) = 052t  1 <alt tag = the integral from 0 to 5 of quantity2t minus 1>dt c. g(x) = 152t  <alt tag = the integral from 1 to 5 of 2t>dt d. g(x) = 15t 2  1<alt tag = the integral from 1 to 5 of the quantity t squared minus 1>dt 2) The graph shown below is f(x) = 3x + 2. What is the integral that defines the area under this line between x = 1 and x = 5? X Y -4 -2 2 4 -2 8 6 4 2 0 Created with a trial version of Advanced Grapher - http://www.alentum.com/agrapher/ <alt tag = a graph of a straight line of slope 3 and a y-intercept of 2>@ The integral function is g(x) = 153t  2 <alt tag = the integral from 1 to 5 of the quantity 3t plus 2>dt. a. g(x) = 153t  2 <alt tag = the integral from 1 to 5 of the quantity 3t minus 2>dt *b. g(x) = 153t  2 <alt tag = the integral from 1 to 5 of the quantity 3t plus 2>dt c. g(x) = 153t  <alt tag = the integral from 1 to 5 of 3t>dt d. g(x) = 14 3t 2  2 <alt tag = the integral from 1 to 4 of the quantity 3 times t squared plus 2>dt 3) The graph shown below is f(x) = x + 3. What is the integral that defines the area under this line between x = 1 and x = 5? X Y -4 -2 2 4 -2 8 6 4 2 0 Created with a trial version of Advanced Grapher - http://www.alentum.com/agrapher/ <alt tag = a graph of a straight line of slope 1 and a y-intercept of 3> @ The integral function is g(x) = 15t  3 <alt tag = the integral from 1 to 5 of the quantity t plus 3>dt. a. g(x) = 25t  3 <alt tag = the integral from 2 to 5 of the quantity t plus 3>dt b. g(x) = 15t <alt tag = the integral from 1 to 5 of t>dt *c. g(x) = 15t  3 <alt tag = the integral from 1 to 5 of the quantity t plus 3>dt d. g(x) = 15t 2  3 <alt tag = the integral from 1 to 5 of the quantity t squared plus 3>dt 4) The graph shown below is f(x) = x2. What is the integral that defines the area under this line between x = -1 and x = 1?X Y -4 -2 2 4 -2 8 6 4 [Show More]

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