AQA_A Level Physics Paper 2_Mark Scheme 2022 | Practice Paper 2

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AQA_A Level Physics Paper 2_Mark Scheme 2022 | Practice Paper 2 Section A 1 (a) (i) Heating result in increased pressure because of: 2 more collisions (of molecules) with wall per second OR more f... requent collisions of molecules with walls ✓ greater momentum change (of molecules)per collision ✓ (ii) (Heating results in) faster molecules so more momentum change 2 per collision ✓ (To maintain same pressure] volume increases to reduce the number of collisions per second ✓ (b) (i) ✓ 2 5.9(4) × 10–3 m3 ✓ (ii) 2 ✓ = 1.0 × 103 K (1000 K) ✓ (Total 8 marks) A-LEVEL PHYSICS MARK SCHEME Practice Paper 2 Maximum marks: 85 View detailed guidance on the conclusions you can draw from your students' performance in these papers on the MERiT welcome page. Understand how your students compare with others and target revision effectively by entering marks into MERiT. This document is licensed to Haggerston School - MB260045Page 2 2 (a) (i) mean kinetic energy ( = 3 / 2 kT) = 3 / 2 × 1.38 × 10-23 × (273 + 22) 1 = 6.1 × 10-21 ) ✓ Note 1sf answer 6 × 10-21 J is not given mark (ii) mass of krypton atom 2 = 0.084 / 6.02 × 10-23✓ ( = 1.4 × 10-25 kg) ( = 2 × mean kinetic energy / mass = 2 × 6.1 × 10-21/ 1.4 x 10-25 ) = 8.7 - 8.8 ×104✓ 1st mark is for the substitution which will normally be seen within a larger calculation. allow CE from (i) working must be shown for a CE no calculation marks if mass has a physics error i.e. no division by NA note for CE answer = (i) × 1.43 x 1025 (b) (at the same temperature) the mean kinetic energy is the same ✓ 2 OR gases have equal OR mass is inversely proportional to mean square speed OR m ∝ 1 ̅̅̅̅2? or mean square speed of krypton is less ✓ 1st mark requires the word mean / average or equivalent in an algebraic term 2nd mark ‘It’ is taken to mean krypton. So, ‘It is less’ can gain a mark allow ‘heavier’ to mean more massive’ allow vague statements like speed is less for 2nd mark but not in the first mark (Total 5 marks) 3 (a) heat water to 100 °C, energy (= 190 × 4200 × 77) = 61.4(MJ) ✓ 3 vapourise water, energy (=190 × 2.3 × l06) = 440(MJ) ✓ (437MJ) energy transferred (per sec) = (437 + 61.4) MJ = 498.4 MJ ✓ (seen to 3 or more sf) (b) mass of rocks (= 4.0 × 106 × 3200) 4 = 1.3 × 1010(kg) ✓ (1.28 × 1010) temperature fall of ΔT in one day, energy removed (= 1.28 ×1010 × 850 × ΔT) = 1.1 × 1013 ΔT ✓ (1.09 x 1013 AT) (allow C.E. for value of mass of rocks) energy transfer in one day (= 500 × 106 × 3600 × 24) = 4.3 × 1013 (J) ✓ - -- - [Show More]

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