Health Care > EXAM > CHEM 14BL DR. OW PRACTICE MIDTERM EXAM V2 QUESTIONS CALCULATIONS WITH ANSWERS 2023 (All)
CHEM 14BL DR. OW PRACTICE MIDTERM EXAM V2 QUESTIONS CALCULATIONS WITH ANSWERS 2023 1. Consider the following calculation: [(12.635 +/- 0.005) / (5.967 +/- 0.003)] + (0.478 +/- 0.004) Cal... culate the percent relative error and the absolute error. .005 / 12.635 = .000396 .003 / 5.967 = .000503 .000396 + .000503 = .000899 = total relative error for the division in parentheses 12.635 / 5.967 = 2.11747947 .000899 x 2.11747947 = .0019 = total absolute error for the division in parentheses For the final addition step, let’s sum the absolute errors. .0019 + .004 = .0059 ~ .006 = total absolute error Now we can find the total % relative error 2.11747947 + 0.478 = 2.59547947 .0059 / 2.59547947 = .002311 ~ .002 = 0.2% = total % relative error [Show More]
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