Mathematics > QUESTIONS & ANSWERS > Questions and Answers > Colorado Technical University MATH 451 Project Crashing (All)
Colorado Technical University MATH 451 Project Crashing Learn: Project Crashing The decision variables in the LP model include the __________ and crash amounts. crash times end times start... times duration times It is logical that the crash cost is __________ the standard cost of an activity. less than lower than more than the same as Associated with the standard time is the __________ cost of an activity. expected reduced crash normal Activity Standard Time Crash Time Standard Cost Crash Cost A 3 2 $20,000 $22,000 B 2 1 $14,000 $15,000 C 4 2 $16,000 $20,000 D 3 1 $15,000 $18,000 The crash cost per period for activity A is __________. $20,000 -$2,000 ($20,000 - $22,000) / 3 - 2 $2,000 Crash cost per period = (__________) / (Standard time - Crash time) Learn: Project Crashing Standard cost Difference in crash cost and standard cost Crash cost Standard cost - Crash cost Crash time is the __________ duration of an activity. shortest longest slowest lengthiest Activity Standard Time Crash Time Standard Cost Crash Cost A 3 2 $20,000 $22,000 B 2 1 $14,000 $15,000 C 4 2 $16,000 $20,000 D 3 1 $15,000 $18,000 If activity D is chosen for crashing, the project could be shortened by __________ week(s). 0 3 4 1 The process of shortening the duration of a project in the __________ manner is crashing. most costly least inexpensive most expensive least expensive The decision variables in the LP model include the __________ and crash amounts. Learn: Project Crashing crash times start times duration times end times Associated with the standard time is the __________ cost of an activity. expected crash reduced normal When selecting an activity to crash, the activity should __________. not be on the critical path be the first activity in the project network be on the critical path have the highest crash cost per period Crashing activities common to more than one __________ may be cheapest. week project critical path project network Activity Standard Time Crash Time Standard Cost Crash Cost A 3 2 $20,000 $22,000 B 2 1 $14,000 $15,000 Learn: Project Crashing C 4 2 $16,000 $20,000 D 3 1 $15,000 $18,000 For the critical path of A-B-D, the project has to be shortened by 2 weeks. The crash could be __________ and have an additional total cost of $2,500– $3,000. 2 weeks in activity A activities A and C for 1 week each 2 weeks in activity D activities B and C for 1 week each When using a LP model for crashing, the objective is to __________. minimize the project completion time minimize the total cost maximize the total cost maximize the project completion time [Show More]
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