Chem 120 Exam 3 Review Guide 2023-2024 With 100% Verified Answers

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Reduction/oxidation (Redox Chemistry) LEO the lion goes GER Oxidation: Loss of Electrons is Oxidation (LEO) Reduction: Gaining of Electrons is Reduction (GER)Are each of the following oxidized or ... reduced? Fe2+ → Fe0 Fe is reduced as the charge is becoming more negative (meaning that the Fe gained e - ) O2- → O0 O is being oxidized as the charge is becoming more positive (loosing e - ) Cu+1 → Cu2+ Cu is being oxidized as the charge is becoming more positive (loosing e - )Agents Oxidizing agent: Contains the species being reduced. Oxidizes another species in the reaction by accepting electrons (becoming reduced in the process). Reducing agent: Contains the species being oxidized. Reduces another species in the reaction by donating electrons (becoming oxidized in the process). What is the oxidizing agent in this redox reaction? Cu2+ + Zn0 → Cu0 + Zn2+ Answer: Cu2+ is the oxidizing agent as this species accepted electrons from the Zn0 , and in the processes, became reduced. In other words, the Cu2+ oxidized the Zn0 . What is the reducing agent in this redox reaction: V4+ + Cu+ → Cu+5 + V0 Answer: Cu+ is the reducing agent, as this species donated electrons to the V4+ , and in the process, became oxidized. In other words, the Cu+ reduced the V4+ . Assigning Oxidation Numbers What are the oxidation numbers on: 2 H2 + O2 → 2 H2O Answer: 2 H 0 + O 0 → 2 H+1 O2- What is the reducing agent for the equation above? Answer: H2 is the reducing agent as this species reduced the O from 0 to -2. 2 2 What is the oxidizing agent in the redox equation: V + O2 → VO2 Answer: V0 + O 0 → V4+O 2- O2 is the oxidizing agent because the O2 accepted electrons from the V, causing the V to become oxidized. [Show More]

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